#!/bin/bash

# Figure out what the most common timestamp is in the top level of a
# list of directories, and spit it out.

# Why is this useful?  Because the NetApp snapshot directory is listed
# as... nightly.0, nightly.1, etc... and all the timestamps at that level
# are identical.  This script lets you quickly find which directory is
# from a particular day.  Also we are lazy.

# requires... bash, awk, uniq, sort, tail, tr, printf

# This script  lives at http://www.elifulkerson.com

# if we didn't get a target, go ahead and use * in the local directory
if [ $# = 0 ]
then
   dirs=`ls`
else
   dirs=$*
fi

echo "Avg Date   Directory";
echo "---------- ---------";

for file in $dirs; do
  if [ -d $file ]
  then
    ls -al $file |awk '{print $6}'|uniq -c|sort -n|tail -n 1|awk '{print $2}'|tr '\n' ' '
    printf "%s \n" $file
  fi
done;